[આપેલ $: R =8.31 \,J \,K ^{-1} \,mol ^{-1}, \log 1.33=0.1239$ $\ln 10=2.3]$
$t =0 \quad\quad1 \,mol$
$t = t\quad \quad(1-0.5) \,mol \quad \quad 0.5 \times 2\,mol$
$\quad\quad\quad\quad=0.5 \,mol \quad\quad\quad 1\, mol$
$k _{ p }=\frac{\left(\frac{1}{1.5} \times 1\right)^{2}}{\left(\frac{0.5}{1.5} \times 1\right)}=\frac{1}{0.75}=\frac{100}{75}$
$=1.33$
$\Delta G ^{0}=- RT \ell nk _{ P }$
$=-8.31 \times 300 \times \ell n (1.33)=-710.45\, J / mol$
$=-710 \,J / mol$.
$N_2 + 3H_2 \rightleftharpoons 2NH_3 \,;$ $K_1$
$N_2 + O_2 \rightleftharpoons 2NO\,;$ $K_2$
$H_2 + 2 O_2 \rightleftharpoons H_2O\,;$ $K_3$
તો પ્રક્રિયા $2NH_3 + \frac{5}{2} \overset K \leftrightarrows 2NO + 3H_2O$ નો સંતુલન અચળાંક $(K)$ ...... થશે.
$\mathrm{X} \rightleftharpoons \mathrm{Y} ; \mathrm{K}_1=1.0$
$\mathrm{Y} \rightleftharpoons \mathrm{Z} ; \mathrm{K}_2=2.0$
$\mathrm{Z} \rightleftharpoons \mathrm{W} ; \mathrm{K}_3=4.0$
$\mathrm{x} \rightleftharpoons \mathrm{w}$ પ્રક્રિયા માટે સંતુલન અયળાંક શોધો.