[આપેલ $: R =8.31 \,J \,K ^{-1} \,mol ^{-1}, \log 1.33=0.1239$ $\ln 10=2.3]$
$t =0 \quad\quad1 \,mol$
$t = t\quad \quad(1-0.5) \,mol \quad \quad 0.5 \times 2\,mol$
$\quad\quad\quad\quad=0.5 \,mol \quad\quad\quad 1\, mol$
$k _{ p }=\frac{\left(\frac{1}{1.5} \times 1\right)^{2}}{\left(\frac{0.5}{1.5} \times 1\right)}=\frac{1}{0.75}=\frac{100}{75}$
$=1.33$
$\Delta G ^{0}=- RT \ell nk _{ P }$
$=-8.31 \times 300 \times \ell n (1.33)=-710.45\, J / mol$
$=-710 \,J / mol$.
$\left( 2 \right)\,{N_2}\left( g \right) + {O_2}\left( g \right) \rightleftharpoons 2NO\left( g \right)\,,\,{K_2}$
$\left( 3 \right)\,{H_2}\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \rightleftharpoons {H_2}O\left( g \right)\,,\,{K_3}$
તો $K_1 , K_2$ , અને $K_3$ ના $(K_4)$ સંદર્ભમાં નીચેની પ્રક્રિયા સમીકરણ માટે સંતુલન અચળાંક જણાવો.
$2N{H_3}\left( g \right) + \frac{5}{2}{O_2}\left( g \right) \rightleftharpoons 2NO\left( g \right) + 3{H_2}O\left( g \right)$
(આપેલ: $\mathrm{R}=0.082 \mathrm{~L} \mathrm{~atm} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$ )
(ઉપયોગ $R =8.31\, J\, K ^{-1}\, mol ^{-1} ; \log 2=0.3010$. In $10=$ $2.3, \log 3=0.477$ )