MCQ
$\,$
- A
- B
- ✓
- D
✓
Answer
Correct option: C.
c
The chemical reaction is shown below:
The chemical reaction is shown below:
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In a electrochemical cell
Select reaction which will be favoured in forward direction
$\mathrm{RCONH}_2$ is converted into $\mathrm{RNH}_2$ by means of Hofmann bromamide degradation.
→$Image$
In this reaction, $\mathrm{RCONHBr}$ is formed from which this reaction has derived its name. Electron donating group at phenyl activates the reaction. Hofmann degradation reaction is an intramolecular reaction.
$1.$ How can the conversion of $(i)$ to $(ii)$ be brought about?
$(A)$ $\mathrm{KBr}$ $(B)$ $\mathrm{KBr}+\mathrm{CH}_3 \mathrm{ONa}$ $(C)$ $\mathrm{KBr}+\mathrm{KOH}$ $(D)$ $\mathrm{Br}_2+\mathrm{KOH}$
$2.$ Which is the rate determining step in Hofmann bromamide degradation?
$(A)$ Formation of $(i)$ $(B)$ Formation of $(ii)$ $(C)$ Formation of $(iii)$ $(D)$ Formation of $(iv)$
$3.$ What are the constituent amines formed when the mixture of $(i)$ and $(ii)$ undergoes Hofmann bromamide degradation?
$Image$
give the answer question $1$, $2$, and $3.$
Which of the following $0.05\,M$ aqueous solution will have the lowest freezing point ?
→Product $(A)$ is
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$F{e_2}C{r_2}{O_4} + N{a_2}C{O_3} + {O_2}\xrightarrow{{Fusion}}\left[ X \right]\xrightarrow[{{H_2}O}]{{{H^ + }}}\left[ Y \right]\xrightarrow{{{H_2}{O_2}/{H^ + }}}\left[ Z \right]$
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