MCQ
$2\cos x - \cos 3x - \cos 5x = $
- ✓$16{\cos ^3}x{\sin ^2}x$
- B$16{\sin ^3}x{\cos ^2}x$
- C$4{\cos ^3}x{\sin ^2}x$
- D$4{\sin ^3}x{\cos ^2}x$
$ = 2\cos x\,2{\sin ^2}2x$$ = 4\,\cos x\,{\sin ^2}\,2x $
$= 16\,{\sin ^2}x\,{\cos ^3}x$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.