MCQ
$2\pi\text{cm}^2$ The surface area of a cube whose volume is 64cm3 is:
- A108cm2
- B96cm2
- C64cm2
- D72cm2
Solution:
Given: Volume of cube = 64cm3
⇒ a3 = 64
⇒ a3 = (4)3
⇒ a = 4cm
$\therefore$ Surface Area of cube = 6a2 = 6(4)2 = 96 sq. cm
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