Volume of \(O_{2}\) used
\(=375 \times \frac{20}{100}=75 m l\)
From the reaction of combination
\(m l C_{x} H_{y}\) requires \(=\frac{4 x+y}{4} m l O_{2}\)
\(15\left(\frac{4 x+y}{4}\right)=75\)
So, \(4 x+y=20\)
\(x=3\)
\(y=8\)
\(\therefore C_{3} H_{8}\)

$n - Bu -\equiv\frac{(i) n-BuLi,n - C _{5} H _{11} Cl}{(ii) Lindlar\,\, cat, H _{2}}$
