Question
$\frac{3}{4}(\text{x}-1)=\text{x}-3$

Answer

$\frac{3}{4}(\text{x}-1)=\text{x}-3$ On expanding the brackets on both sides,
we get $=\frac{\text{3x}}{4}-\frac34=\text{x}-3$
Transposing $\frac34\text{x}$ to $R.H.S$. and $3$ to $L.H.S.,$
we get $\Rightarrow3-\frac34=\text{x}-\frac34\text{x}$
$\Rightarrow\frac{12-3}{4}=\frac{4\text{x}-3\text{x}}{4}$
$\Rightarrow\frac{9}{4}-=\frac{\text{x}}{4}$
Multiplying both sides by $4,$
we get $\Rightarrow\text{x}=9$
Verification: Substituting $x = 9$ on both sides,
we get $\frac{3}{4}(9-1)=9-3$
$\frac34\times8=6$
$L.H.S. = R.H.S$.
Hence, verified.

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