Question
$\frac{3}{4}\times\big(\frac{-2}{3}\big )=$ _____.
✓
Answer
GIven,
$\frac{3}{4}\times\big(\frac{-2}{3}\big )$
Product of rational numbers,
$=\frac{\text{Product of numerators}}{\text{Product of denominators}}$
$=\frac{3\times(-2)}{4\times3}=\frac{-6}{12}$
$=\frac{-6+6}{12+6} [$dividing numerator and denominator by $6]$
$=\frac{-1}{2}$
$\frac{3}{4}\times\big(\frac{-2}{3}\big )$
Product of rational numbers,
$=\frac{\text{Product of numerators}}{\text{Product of denominators}}$
$=\frac{3\times(-2)}{4\times3}=\frac{-6}{12}$
$=\frac{-6+6}{12+6} [$dividing numerator and denominator by $6]$
$=\frac{-1}{2}$
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