${\mathop {Br}\limits^0 _2}\,\,\,\, \to \,\,\,\,B{r^ - }$ (રિડક્શન)
${\mathop {Br}\limits^0 _2}\, \to \,\mathop {Br}\limits^{ + 5} O_3^ - $ (ઓક્સિડેશન)
કારણ : $S{O_2}$ એ રિડક્શનકર્તા છે.
$xC{l_2}\, + 6O{H^ - }\, \to \,Cl{O_3}^ - \, + \,yC{l^ - } + 3{H_2}O$
$xMn{O_4}^ - \, + \,y{H_2}S{O_4}\, \to \,2M{n^{2 + }}\, + \,5{H_2}O\, + \,z{e^ - }$