MCQ
$3\text{MnO}_2\ +\ 4\text{Al}\xrightarrow{\ \ \ \ \ \ \ \ \ \ \ }2\text{Al}_2\text{O}_3\ +\ 3\text{Mn}$The reducing agent is :
- A$\mathrm{MnO}_2$
- ✓$\ce{Al}$
- C$\mathrm{Al}_2 \mathrm{O}_3$
- D$\ce{Mn}$
✓
Answer
Correct option: B.
$\ce{Al}$
On the contrary, the oxidation number of $\ce{Al}$ is zero and it changes to $+\ 3$ in $\mathrm{Al}_2 \mathrm{O}_3$.
Hence the ‘oxidation number increases’ so it is an oxidation reaction and $\ce{Al}$ is a reducing agent.
Hence the ‘oxidation number increases’ so it is an oxidation reaction and $\ce{Al}$ is a reducing agent.
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