Question
$3\text{x}-\frac{\text{x}-2}{3}=4-\frac{\text{x}-1}{4}$
✓
Answer
Given, $3\text{x}-\frac{\text{x}-2}{3}=4-\frac{\text{x}-1}{4}$
$\frac{9\text{x}-(\text{x}-2)}{3}=\frac{16-(\text{x}-1)}{4}4(9x - x + 2) = 3(16 - x + 1)$
$4(8x + 2) = 3(-x + 17)$
$32x + 8 = -3x + 51$
$32x + 3x = 51 - 8$
$35x = 43$
$\frac{35\text{x}}{35}=\frac{43}{35}$
$\text{x}=\frac{43}{35}$
$\frac{9\text{x}-(\text{x}-2)}{3}=\frac{16-(\text{x}-1)}{4}4(9x - x + 2) = 3(16 - x + 1)$
$4(8x + 2) = 3(-x + 17)$
$32x + 8 = -3x + 51$
$32x + 3x = 51 - 8$
$35x = 43$
$\frac{35\text{x}}{35}=\frac{43}{35}$
$\text{x}=\frac{43}{35}$
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