Question
$3(x - 3) = 5(2x + 1)$

Answer

$3(x - 3) = 5(2x + 1)$ On expanding the brackets on both sides,
we get $= 3 × x - 3 × 3 = 5 × 2x + 5 × 1 = 3x - 9 = 10x + 5$
Transposing $10x$ to $L.H.S$. and $9$ to $R.H.S.,$
we get $= 3x - 10x = 9 + 5 = -7x = 14$ Dividing both sides by $7,$
we get $=\frac{-7\text{x}}{7}$ $=\frac{-14}{7}$ $=\text{x}=-2$
Verification: Substituting $x = -2$ on both sides,
we get $3(-2 - 3) = 5{2(-2) +1} 3(-5) = 5(-3) -15 = -15 $
$L.H.S. = R.H.S$. Hence, verified.

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