MCQ
$4$ -Pentenoic acid when treated with $I_2$ and $NaHCO_3$ gives
- A$4, 5$ -diiodopentanoic acid
- ✓$5$ -iodomethyl-dihydrofuran- $2$ -one
- C$5$ -iodo-tetrahydropyran- $2$ -one
- D$4$ -pentenolyiodide
✓
Answer
Correct option: B.
$5$ -iodomethyl-dihydrofuran- $2$ -one
b
$(b)$ Iodo lactonization.
$(b)$ Iodo lactonization.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A solution containing $10\,g$ per $dm^3$ of urea (molecular mass $= 60\,g\,mol^{-1}$ ) is isotonic with a $5\%$ solution of a non volatile solute. The molecular mass of this non volatile solute is ........ $g\,mol^{-1}$
→The rate constant $(k)$ of a reaction is measured at different temperatures $(T),$ and the data are plotted in the given figure. The activation energy of the reaction in $kJ\, mol ^{-1}$ is :
→($R$ is gas constant)
Which of the following shall form an octahedral complex
For the following two reactions, which statement is.true?
Reagent $X$ in the given reaction is
→Consider the above reaction, the compound $'A'$ is
→In the electrolysis of aqueous sodium chloride solution which of the half cell reaction will occur at anode?
Reaction : $2Br^{-} + H_2O_2 + 2H^{+} \to Br_2 + 2H_2O$
→take place in two steps :
$(a)$ $Br^{-} + H^{+} + H_2O_2 \xrightarrow{{slow}} HOBr + H_2O$
$(b)$ $HOBr + Br^{-} + H^{+} \xrightarrow{{fast}} H_2O + Br_2$
The order of the reaction is
The major product formed in the following reaction is
→$[Figure]$ $\xrightarrow[{CHC{l_3}}]{{\mathop {\left( {Pyridinium\,chlorochromate} \right)}\limits^{PCC} }}$
The chemical formla of chromite ore is :