MCQ
$4$ -Pentenoic acid when treated with $I_2$ and $NaHCO_3$ gives
- A$4, 5$ -diiodopentanoic acid
- ✓$5$ -iodomethyl-dihydrofuran- $2$ -one
- C$5$ -iodo-tetrahydropyran- $2$ -one
- D$4$ -pentenolyiodide
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Expt. No. | $(A)$ | $(B)$ | Initial Rate |
| $1$ | $0.012$ | $0.035$ | $0.10$ |
| $2$ | $0.024$ | $0.070$ | $0.80$ |
| $3$ |
$0.024$ |
$0.035$ | $0.10$ |
| $4$ | $0.012$ | $0.070$ | $0.80$ |

$\left( {{C_2}O_4^{2 - } = } \right.$ Oxalato $)$