MCQ
$4 \tan ^2 A-4 \sec ^2 A$ is equal to:
- A$-1$
- ✓$-4$
- C$0$
- D$4$
✓
Answer
Correct option: B.
$-4$
We know that
$1+\tan ^2 A=\sec ^2 A$ or
$\tan ^2 A-\sec ^2 A=-1$
The given equation is $4 \tan ^2 A-4 \sec ^2 A$
By taking $4$ as a common $=4\left(\tan ^2 A-\sec ^2 A\right)$
Using equation $(i),$
$\Rightarrow 4 \tan ^2 A-4 \sec ^2 A=4(-1)=-4$
Hence, the correct option is $(b).$
$1+\tan ^2 A=\sec ^2 A$ or
$\tan ^2 A-\sec ^2 A=-1$
The given equation is $4 \tan ^2 A-4 \sec ^2 A$
By taking $4$ as a common $=4\left(\tan ^2 A-\sec ^2 A\right)$
Using equation $(i),$
$\Rightarrow 4 \tan ^2 A-4 \sec ^2 A=4(-1)=-4$
Hence, the correct option is $(b).$
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