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Answer
$\bar{x}=3$ days, $M_0=3$ days, $s=1.10$ days, $j=0$
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(2) $\mathrm{P}=\left\{-\frac{1}{2}, 0,1\right\}, \mathrm{S}=\{10\}$, and rule is $k(x)=10, x \in \mathrm{P}$
(3) $\mathrm{A}=\{2,5,6\}, \mathrm{B}=\left\{1, \frac{3}{2}, \frac{9}{5}, \frac{11}{7}, \frac{13}{6}\right\}$, and rule is $y=\frac{2 x-1}{x+1}, x \in \mathrm{A}$
(4) $\mathrm{B}=\{-1,0,1,3\}, \mathrm{C}=\{-5,-3,-1,1,3\}$, and rule is $h(x)=2 x+3, x \in \mathrm{B}$
The data about the number of runs scored by two cricketers in $10$ matches are as follows. Use this information to determine which cricketer’s game is more skewed.
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For a sequence of $100$ observations, the mean and standard deviation are $40$ and $10$ respectively. In calculating these measures, two observations were taken as $30$ and $70$ instead of $3$ and $27$ by mistake. Find the corrected mean and corrected standard deviation.
Here, $n=100 ; \overline{ x }=40 ; s=10$
Wrong observation $: 30,70$
True observations $: 3,27$
→Here, $n=100 ; \overline{ x }=40 ; s=10$
Wrong observation $: 30,70$
True observations $: 3,27$