MCQ
$4.5$ moles each of hydrogen and iodine heated in a sealed ten litre vessel. At equilibrium, $3$ moles of $HI$ were found. The equilibrium constant for ${H_2}_{(g)}+ {I_2}_{(g)}$ $\rightleftharpoons$ $2HI_{(g)}$ is
- ✓$1$
- B$10$
- C$5$
- D$0.33$
(a) ${N_2} + 3{H_2}$ $ \rightleftharpoons $ $2N{H_3}$
Initial conc. $1$ $3$ $0$
at equilibrium $1-0.81$ $3-2.43$ $1.62$
$0.19$ $0.57$
No. of moles of ${N_2} = \frac{{28}}{{28}} = 1$ $mole$
No. of moles of ${H_2} = \frac{6}{2} = 3$ $mole$
No. of moles of $N{H_3} = \frac{{27.54}}{{17}} = 1.62$ $mole$
${K_c} = \frac{{{{[N{H_3}]}^2}}}{{[{N_2}]\,\,{{[{H_2}]}^3}}} = \frac{{{{[1.62]}^2}}}{{[0.19]\,\,{{[0.57]}^3}}}$$=75$
$2HI$
Initial conc. $4.5$ $4.5$ $0$
$x$ $x$ $2x$
from question $2x = 3$
$x = \frac{3}{2} = 1.5$
So conc. at eqm. $4.5 - 1.5$ of ${H_2}$
$ = 4.5 - 1.5$ of ${I_2}$ and $3$ of $HI$
$K = \frac{{{{[HI]}^2}}}{{[{I_2}]\,\,[{H_2}]}} = \frac{{3 \times 3}}{{3 \times 3}} = 1$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(A)$ Non metals have higher electronegativity than metals.
$(B)$ Non metals have lower ionisation enthalpy than metals.
$(C)$ Compounds formed between highly reactive nonmetals and highly reactive metals are generally ionic.
$(D)$ The non-metal oxides are generally basic in nature.
$(E)$ The metal oxides are generally acidic or neutral in nature.
Student $I$ :- She mixed $B_2H_6$ and $NH_3$
Student $II$ :- He mixed $B_2H_6$ with $THF$ followed by addition of $NH_3$
Which student is expected to get the $CORRECT$ final product ?