Question
$48x^2 – 13x -1 = 0$

Answer

$48 x^2-13 x-1=0 $
$\Rightarrow 48 x^2-16 x+3 x-1=0 $
$ \Rightarrow 16 x(3 x-1)+1(3 x-1)=0 $
$ \Rightarrow(3 x-1)(16 x+1)=0$
$ \Rightarrow 3 x-1=0 \text { or } 16 x+1=0$
$x=\frac{1}{3}$ or $x=\frac{-1}{16}$ are two roots of the equation.

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