MCQ
$50 \,mL$ of $0.1\, M \,CH _{3} COOH$ is being titrated against $0.1 \,M\, NaOH$. When $25\, mL$ of $NaOH$ has been added, the $pH$ of the solution will be $....\,\times 10^{-2}$. (Nearest integer)
(Given : $\left.pK _{ a }\left( CH _{3} COOH \right)=4.76\right)$
$\log 2=0.30$ $\log 3=0.48$ $\log 5=0.69$ $\log 7=0.84$ $\log 11=1.04$
- A$963$
- B$123$
- ✓$476$
- D$596$
