MCQ
When $32.25\,gm$ ethyl chloride dehydro halogenated, if gives $50\%$. Alkene, what is the mass of product.......$gm$ (atomic mass of chlorine = $35.5$)
- A$14 $
- B$28 $
- C$64.5$
- ✓$7$
$64.5$ $28$
$32.25$ $28$
$64.5 \,gm$ ${C_2}{H_5}Cl$ gives $28 \,gm$ of ${C_2}{H_4}$
$32.25\,gm$ ${C_2}{H_5}Cl$ gives $ = \frac{{28 \times 32.25}}{{64.5}}$ = $14 \,gm$ of ${C_2}{H_4}$
Obtained product is $50\%$ so mass of obtained alkene $ = \frac{{14}}{2} = 7\,gm$
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