c
The energy of conductor during discharge is calculated as,

\(U=\frac{1}{2} C V^{2}\)

\(=\frac{1}{2}(5.0 \mu F )(800 V )^{2}\)

\(=\frac{1}{2}\left(5.0 \mu F \times \frac{1 F }{10^{6} \mu F }\right)(800 V )^{2}\)

\(=1.6\) Joule