($R = 0.082\, L\, atm\, mol^{-1}\, K^{-1}$, મોલર દળ $S = 32\, g\, mol^{-1}$, મોલર દળ $N = 14\, g\, mol^{-1}$)
${K_P} = {P_{N{H_3}}}{P_{{H_2}S}}$ $PV = nRT$
${K_P} = \frac{{0.98}}{2} \times \frac{{0.98}}{2}$ $P \times 3 = 0.06 \times 0.0821 \times 600$
$P = \frac{{0.06 \times 0.0821 \times 200}}{3}$
${K_P} = 0.243$ $P = 0.98\,$
$N_2 + 3H_2 \rightleftharpoons 2NH_3 \,;$ $K_1$
$N_2 + O_2 \rightleftharpoons 2NO\,;$ $K_2$
$H_2 + 2 O_2 \rightleftharpoons H_2O\,;$ $K_3$
તો પ્રક્રિયા $2NH_3 + \frac{5}{2} \overset K \leftrightarrows 2NO + 3H_2O$ નો સંતુલન અચળાંક $(K)$ ...... થશે.