Question
$6(1 - 4x) + 7(2 + 5x) = 53$
✓
Answer
$6(1 - 4x) + 7(2 + 5x) = 53$ On expanding the brackets,
we get $(6 \times 1) - (6 \times 4x) + (7 \times 2) + (7 \times 5x) $
$= 53 6 - 24x + 14 + 35x $
$= 53 6 + 14 + 35x - 24x $
$= 53 20 + 11x $
$= 53$
Subtracting $20$ from both sides,
we get $20 + 11x - 20 = 53 - 20 11x = 33$
Dividing both sides by $11,$
we get $\frac{\text{11x}}{11}=\frac{33}{11}$
$\text{x}=3$
Verification: Substituting $x = 3$ in $L.H.S.,$
we get $= 6(1 - 4 \times 3) + 7(2 + 5 \times 3) $
$= 6(1 - 12) + 7(2 + 15) = 6(-11) + 7(17) $
$= -66 + 119 = 53 $
$= R.H.S. L.H.S. $
$= R.H.S.$
Hence, verified.
we get $(6 \times 1) - (6 \times 4x) + (7 \times 2) + (7 \times 5x) $
$= 53 6 - 24x + 14 + 35x $
$= 53 6 + 14 + 35x - 24x $
$= 53 20 + 11x $
$= 53$
Subtracting $20$ from both sides,
we get $20 + 11x - 20 = 53 - 20 11x = 33$
Dividing both sides by $11,$
we get $\frac{\text{11x}}{11}=\frac{33}{11}$
$\text{x}=3$
Verification: Substituting $x = 3$ in $L.H.S.,$
we get $= 6(1 - 4 \times 3) + 7(2 + 5 \times 3) $
$= 6(1 - 12) + 7(2 + 15) = 6(-11) + 7(17) $
$= -66 + 119 = 53 $
$= R.H.S. L.H.S. $
$= R.H.S.$
Hence, verified.
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