MCQ
6.24 × 1019 electrons is equal approximately to:
- A10 coulombs.
- B96500 coulombs.
- Cone electron volt.
- D0.1F.
Explanation:
Since $ 6.24 × 10^{18}$ electrons = 1 coulomb
$\therefore 6.24 × 10^{19}$ electrons = 10 coulomb
$\Big(\frac{6.24\times10^{19}}{6.24\times10^{18}}\Big)$
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$\underset{1}{\mathop{\begin{matrix}
O\,\,\,\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}COCHC{{H}_{3}} \\
\end{matrix}}}\,$ $\underset{2}{\mathop{\begin{matrix}
\,\,\,\,O \\
\,\,\,\,|| \\
C{{H}_{3}}CCl \\
\end{matrix}}}\,$ $\underset{3}{\mathop{\begin{matrix}
O\,\,\,\,\,\,\,\,\, \\
||\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}CNHC{{H}_{3}} \\
\end{matrix}}}\,$
