$62.5 \times {10^{18}}$ electrons per second are flowing through a wire of area of cross-section $0.1\,{m^2}$, the value of current flowing will be ............ $A$
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$i = \frac{{ne}}{t} = \frac{{62.5 \times {{10}^{18}} \times 1.6 \times {{10}^{ - 19}}}}{1} = 10\,ampere$
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