Four ammeters with identical internal resistances $r$ and a resistor of resistance $R$ are connected to a current source as shown in figure. It is known that the reading of the ammeter $A_1$ is $I_1 = 3\ A$ and the reading of the ammeter $A_2$ is $I_2 = 5\ A$ . Determine the ratio of the resistances $R/r$ .
Diffcult
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$\mathrm{V}_{0}-5 \mathrm{r}-7 \mathrm{r}$
$=\mathrm{V}_{0}-12 \mathrm{r}$
$\mathrm{V}_{0}-3 \mathrm{r}-1 \times \mathrm{R}=\mathrm{V}_{0}-12 \mathrm{r}$
$\Rightarrow \mathrm{R}=9 \mathrm{r}$
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