$64$ drops each having the capacity $C$ and potential $V$ are combined to form a big drop. If the charge on the small drop is $q$, then the charge on the big drop will be
A$2\,q$
B$4\,q$
C$16\,q$
D$64\,q$
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D$64\,q$
d (d) By using $Q = nq$$⇒$ $Q = 64\,q$
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