MCQ
$8 g$ of He is equal to:
- A$4$ moles.
- ✓$12.044 \times 10^{23}$ atoms.
- C$1.2044 \times 10^{23}$ atoms.
- D$3 \times 10^{23}$ atoms.
$8g$ of he $= 2$ moles of He aprox ($1$ mole of he $= 4.003g)$
$= 2 \times 6.0221 \times 10^{23}$
(1 mole is amount of substance that contains avogadro no. of particles)
$= 12.0442 \times 10^{23}$atoms.
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