MCQ
$8\, mol$ of $AB_3(g)$ are introduced into a $1.0\, dm^3$ vessel. If it dissociates as $2AB_3(g)  \rightleftharpoons  A_2(g) + 3 B_2(g)$ At equilibrium, $2\,mol$ of $A_2$ are found to be present. The equilibrium constant of this reaction is
  • A
    $36$
  • B
    $3$
  • $27$
  • D
    $2$

Answer

Correct option: C.
$27$
c
$\mathop {\mathop {\mathop {2A{B_3}}\limits_8 }\limits_{8 - 2x\,\,\,\,x} }\limits_4  \rightleftharpoons \mathop {\mathop {\mathop {{A_2}}\limits_0 }\limits_{3x} }\limits_2  + \mathop {\mathop {\mathop {3{B_2}}\limits_0 }\limits_{} }\limits_6 $

${K_c} = \frac{{(2){{(6)}^3}}}{{{{(4)}^2}}} = 27$

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