MCQ
${{8}^{2n}}-{{62}^{2n+1}}$ ને $9$ વડે ભાગતાં શેષ ........ મળે.
- ✓$2$
- B$7$
- C$8$
- D$0$
$8=-1 (|9|)$ તથા $62=-1(|9|)$
$ \therefore 8^{2n}- (62)^{2n+1}=[(-1)^{2n}-(-1)^{2n+1}](mod \ 9)$
$=(1+1) \ (mod 9)\\ =2 \ (mod 9)$
$ \therefore 8^{2n}- (62)^{2n+1}$ ને $9$ વડે ભાગતા શેષ $2$ મળે.
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$ = \tan \alpha \tan \beta \tan \gamma $, તો $(\sec \alpha - \tan \alpha )(\sec \beta - \tan \beta )$$(\sec \gamma - \tan \gamma ) = $