| Element | Percentage | Mole | Mole ratio |
| \(C\) | \(85.8\) | \(\frac{85.8}{12}=7.15\) | \(1\) |
| \(H\) | \(14.2\) | \(\frac{14.2}{1}=14.2\) | \(2\) |
Empirical formula \(\left( CH _2\right)\)
\(14 \times n=84\)
\(n =6\)
\(\therefore\) Molecular formula \(C _6 H _{12}\)

$1.\,\,CH_3-C \equiv C -CH_3$
$2.\,\,CH_3 - CH_2 - CH_2 - CH_3$
$3. \,\,CH_3 - CH_2C \equiv CH$
$4.\,\,CH_3 - CH = CH_2$
