MCQ
$8\,g \,O_2$ has same number of atoms as that in
- A$14g\, CO$
- ✓$7g \,CO$
- C$11g\, CO_2$
- D$22g\, CO_2$
✓
Answer
Correct option: B.
$7g \,CO$
b
mole $(\mathrm{n})=\frac{\text { weight }(\mathrm{w})}{\text { atomic wt. }}=\frac{\mathrm{No.} \text { of } \operatorname{atom}(\mathrm{N})}{\mathrm{N}_{\mathrm{A}}}$
mole $(\mathrm{n})=\frac{\text { weight }(\mathrm{w})}{\text { atomic wt. }}=\frac{\mathrm{No.} \text { of } \operatorname{atom}(\mathrm{N})}{\mathrm{N}_{\mathrm{A}}}$
in $8\, \mathrm{g}\, \mathrm{O}_{2}$ No. of atom
$\frac{8}{16}=\frac{N}{N_{A}} \Rightarrow N=\frac{N_{A}}{2}$
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