MCQ
$n-$propyl bromide on treatment with ethanolic potassium hydroxide produces
- APropane
- ✓Propene
- CPropyne
- DPropanol
✓
Answer
Correct option: B.
Propene
b
(b) $\mathop {C{H_3} - C{H_2} - C{H_2} - Br}\limits_{n - {\rm{Propyl bromide}}} + KOH \xrightarrow{C_2H_5OH} \mathop {C{H_3} - CH = C{H_2}}\limits_{{\rm{Propene}}} + KBr + {H_2}O$
(b) $\mathop {C{H_3} - C{H_2} - C{H_2} - Br}\limits_{n - {\rm{Propyl bromide}}} + KOH \xrightarrow{C_2H_5OH} \mathop {C{H_3} - CH = C{H_2}}\limits_{{\rm{Propene}}} + KBr + {H_2}O$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Vapour density of a metal chloride is $66$. Its oxide contains $53\%$ metal. The atomic weight of the metal is
→Which of the following gas molecules have maximum value of enthalpy of physisorption?
Light, a well-known from of energy, is treated as a from of matter, by saying that it consists of:
The process in which higher hydrocarbons are broken down into lower hydrocarbons by controlled pyrolysis, is called
A species H2O+ pyramidal in shape. The number of lone pairs of electrons is:
One mole of an ideal gas at $900 K$, undergoes two reversible processes, $I$ followed by $II$, as shown below. If the work done by the gas in the two processes are same, the value of $\ln \frac{V_3}{V_2}$ is. . . . . . . . ( $U$ : internal energy, $S$ : entropy, $p$ : pressure, $V$ : volume, $R$ : gas constant) (Given: molar heat capacity at constant volume, $C_{V, m }$ of the gas is $\frac{5}{2} R$ )
→( $U$ : आंतरिक ऊर्जा (internal energy), $S$ : एंट्रॉपी (entropy), $p$ : दाब (pressure), $V$ : आयतन (volume), $R$ : गैस नियतांक (gas constant)
(दिया गयाः स्थिर आयतन पर गैस की मोलर ऊष्माधारिता (molar heat capacity at constant volume), $C_{V, m }$ का मान $\frac{5}{2} R$ है)
If uncertainty in the position of an electron is zero, the uncertainty in its momentum would be
The correct order for the decrease in atomic radii is
The $IUPAC$ name of the following compound is $\mathop {\mathop {C{H_3} - CH - C{H_2}C{H_2}C{H_3}}\limits_{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} }\limits_{CH{{(C{H_3})}_2}\,\,\,\,} $
→Nitrogen has the electronic configuration $1{s^2}2{s^2}2p_x^12p_y^12p_z^1$ and not $1{s^2}2{s^2}2p_x^22p_y^12p_z^0$ which is determined by
→