MCQ
$9y^2- 16x - 12y - 57 = 0$ પરવલયની અક્ષ શોધો.
- A$3y = 2$
- B$2x = 3$
- C$x + 3y = 3$
- D$y = 3$
$ \Rightarrow \,\,{\left( {3y\, - \,\,2} \right)^2}\,\, = \,\,16x\,\, + \;\,57$$ \Rightarrow \,\,{\left( {y\,\, - \,\,\frac{2}{3}} \right)^2}\,\, = \,\,\frac{{16}}{9}\,\,\left( {x\,\, + \,\,\frac{{61}}{{16}}} \right)$
અક્ષનું સમીકરણ $y - 2/3 = 0 ==> 3y = 2$
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