Question
A $100$ mark examination was administered to a class of $50$ students. Despite only integer marks being given, the average score of the class was $47.5$. Then, the maximum number of students who could get marks more than the class average is

Answer

d
(d)

Total number of students $=50$

Average marks of student $=47.5$

$\therefore$ Total marks of students

$=50 \times 47.5=2375$

Now, the student get integer marks Hence, the maximum number of students we will divide total mark by $48$.

$\frac{2375}{48}=49$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let $\overrightarrow{ u }, \overrightarrow{ v }$ and $\overrightarrow{ w }$ be vectors in three-dimensional space, where $\overrightarrow{ u }$ and $\overrightarrow{ v }$ are unit vectors which are not perpendicular to each other and $\overrightarrow{ u } \cdot \overrightarrow{ w }=1, \overrightarrow{ v } \cdot \overrightarrow{ w }=1, \overrightarrow{ w } \cdot \overrightarrow{ w }=4$

If the volume of the parallelopiped, whose adjacent sides are represented by the vectors $\overrightarrow{ u }, \overrightarrow{ v }$ and $\overrightarrow{ w }$ , is $\sqrt{2}$, then the value of $|3 \vec{u}+5 \vec{v}|$ is. . . . .

The number of non-empty subsets of the set $\{1, 2, 3, 4\}$ is
For the primitive integral equation $ydx + y^2dy = xdy$ ; $x \in  R$ , $y > 0$ , $y = y(x)$ , $y(1) = 1$ , then $y(-3)$ is 
Let $f(x)=x^3+x^2 f^{\prime}(1)+x f^{\prime \prime}(2)+f^{\prime \prime \prime}(3), x \in R$ Then $f^{\prime}(10)$ is equal to ..............
Consider a triangle having vertices $A(-2,3), B(1,9)$ and $C(3,8)$. If a line $L$ passing through the circum-center of triangle $\mathrm{ABC}$, bisects line $\mathrm{BC}$, and intersects $\mathrm{y}$-axis at point $\left(0, \frac{\alpha}{2}\right)$, then the value of real number $\alpha$ is $.....$
Let $x$ and $y$ be two $2-$digit numbers such that $y$ is obtained by reversing the digits of $x$. Suppose they also satisfy $x^2-y^2=m^2$ for some positive integer $m$. The value of $x+y+m$ is
Let $P$ be a non-zero polynomial such that $P(1+x)=P(1-x)$ for all real $x$ and $P(1)=0$. Let $m$ be the largest integer such that $(x-1)^m$ divides $P(x)$ for all such $P(x)$. Then, $m$ equals
Let $P$ be the point $(10,-2,-1)$ and $Q$ be the foot of the perpendicular drawn from the point $\mathrm{R}(1,7,6)$ on the line passing through the points $(2,-5,11)$ and $(-6,7,-5)$. Then the length of the line segment $\mathrm{PQ}$ is equal to ..........
Let $A=\left[\begin{array}{lll}x & y & z \\ y & z & x \\ z & x & y\end{array}\right], \quad$ where $x, y$ and $z$ are real numbers such that $x + y + z >0$ and $xyz =2$ If $A ^{2}= I _{3},$ then the value of $x ^{3}+ y ^{3}+ z ^{3}$ is ............
The total number of terms in the expansion of ${(x + a)^{100}} + {(x - a)^{100}}$ after simplification will be