A 100, W bulb B_1, and two 60,W bulbs B_2 and B_3, are connected to a 250, V source, as shown in the figure. Now

Q: A $100\, W$ bulb $B_1$, and two $60\,W$ bulbs $B_2$ and $B_3$, are connected to a $250\, V$ source, as shown in the figure. Now $ W_1, W_2$ and $W_3$ are the output powers of the bulbs $B_1, B_2$ and $B_3$, respectively. Then

d $P = \frac{{{V^2}}}{R}$ so $R = \frac{{{V^2}}}{P}$ ${R_1} = \frac{{{V^2}}}{{100}}$ and ${R_2} = {R_3} = \frac{{{V^2}}}{{60}}$ Now ${W_1} = \frac{{{{(250)}^2}}}{{{{({R_1} + {R_2})}^2}}}.{R_1}$, ${W_2} = \frac{{{{(250)}^2}}}{{{{({R_1} + {R_2})}^2}}}.{R_2}$ and ${W_3} = \frac{{{{(250)}^2}}}{{{R_3}}}$ ${W_1}:{W_2}:{W_3} = 15:25:64$ or ${W_1} < {W_2} < {W_3}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

A $100\, W$ bulb $B_1$, and two $60\,W$ bulbs $B_2$ and $B_3$, are connected to a $250\, V$ source, as shown in the figure. Now $ W_1, W_2$ and $W_3$ are the output powers of the bulbs $B_1, B_2$ and $B_3$, respectively. Then

A${W_1} > {W_2} = {W_3}$
B${W_1} > {W_2} > {W_3}$
C${W_1} < {W_2} = {W_3}$
D${W_1} < {W_2} < {W_3}$

IIT 2002, Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Download App

Similar Questions

1
Two $220\; V , 100 \;W$ bulbs are connected first in series and then in parallel. Each time the combination is connected to a $220 \;V \;AC$ supply line. The power drawn by the combination in each case respectively will be
View Solution
2
In an electrolyte $3.2 \times {10^{18}}$ bivalent positive ions drift to the right per second while $3.6 \times {10^{18}}$ monovalent negative ions drift to the left per second. Then the current is
View Solution
3
A constant voltage is applied between the two ends of a metallic wire. If both the length and the radius of the wire are doubled, the rate of heat developed in the wire
View Solution
4
The measurement of ammeter in the following circuit is ................... $A$ (Assuming ideal ammeter)
View Solution
5
The e.m.f. of a cell is $E\, volts$ and internal resistance is $r$ $ohm$. The resistance in external circuit is also $r$ $ohm$. The p.d. across the cell will be
View Solution
6
In given circuit find potential difference between $P$ and $Q$ .................. $V$
View Solution
7
The length of a potentiometer wire is $1200\; \mathrm{cm}$ and it carries a current of $60 \;\mathrm{mA}$. For a cell of $emf\;5\; \mathrm{V}$ and intemal resistance of $20\; \Omega,$ the null point on it is found to be a $1000\; \mathrm{cm} .$ The resistance of whole wire is .............. $\Omega$
View Solution
8
In the circuit shown in the adjoining figure, the reading of ammeter $A$ is ................ $\mathrm{A}$
View Solution
9
Find the charge in steady state of the capacitor. (in $nC)$
View Solution
10
The equivalent resistance of the arrangement of resistances shown in adjoining figure between the points $A$ and $B$ is ............... $ohm$
View Solution

Download our appand get started for free

Similar Questions

Download our app
and get started for free