Find the charge in steady state of the capacitor. (in $nC)$
AIIMS 2019, Medium
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The capacitor is in parallel to $100 \Omega$ resistance of volt will be as,
$V = IR$
Substitute the values,
$V =\left(\frac{12}{300}\right) 200$
$=8 V$
The expression of charge is given by,
$q = cV$
$=1 \times 8$
$=8 nC$
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