When wire is stretched to double of its length, then resistance becomes 4 times
$R _{ W }=4 R _{ X }=2 R _{ Y }$
$\frac{ R _{ X }}{ R _{ Y }}=\frac{1}{2}$
So. $\frac{\ell_{ X }}{\ell_{ y }}=\frac{1}{2}$




Statement $I$ : A uniform wire of resistance $80\,\Omega$ is cut into four equal parts. These parts are now connected in parallel. The equivalent resistance of the combination will be $5\,\Omega$.
Statement $II :$ Two resistance $2\,R$ and $3\,R$ are connected in parallel in a electric circuit. The value of thermal energy developed in $3\,R$ and $2\,R$ will be in the ratio $3:2.$
In the light of the above statements, choose the most appropriate answer from the options given below