Question
A $2\ kg$ object is floating at rest, acted upon by only force as indicated in figure. Find the total work done by the force in $3\ sec$ ..................... $\mathrm{J}$
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Answer
Area $=\mathrm{m}\left[\mathrm{v}_{f}-\mathrm{v}_{\mathrm{i}}\right]$
$20-10=2\left[v_{t}-0\right], v_{f}=5$
$\mathrm{W}=\frac{1}{2} \mathrm{m}\left[\mathrm{v}_{0}^{2}-\mathrm{v}_{1}^{2}\right]$
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