MCQ
A $3p$ orbital has
- ATwo spherical nodes
- BTwo non-spherical nodes
- ✓One spherical and one non-spherical nodes
- DOne spherical and two non-spherical nodes
Number of spherical node $=n-1-1$
Number of non-spherical node $=1$
For $3 p$ subshell, $n=3$ and $l=1$
$\therefore$ The number of spherical node $= n -l-1=3-1-1=1$
and the number of non-spherical node $=l=1$.
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$2MnO_4^ - + 5{C_2}O_4^ - + 16{H^ + } \to 2M{n^{ + + }} + 10C{O_2} + 8{H_2}O$
Here $20\, mL$ of $0.1\, M\, KMnO_4$ is equivalent to