MCQ
$A + B$ $\rightleftharpoons$ $C + D$. If finally the concentration of $A $ and $B$ are both equal but at equilibrium concentration of $ D$ will be twice of that of $A$ then what will be the equilibrium constant of reaction.
  • A
    $4 / 9$
  • B
    $9/4$
  • C
    $1/9$
  • $4$

Answer

Correct option: D.
$4$
(d) $A + B $ $ \rightleftharpoons $ $C + D$

      $x$        $x$        $0$       $0$ 

                           $2x$     $2x$

${K_c} = \frac{{[C][D]}}{{[A][B]}} = \frac{{2x\,.\,2x}}{{x\,.\,x}} = 4$

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