Question
$(a+b)^2=a^2+b^2$
✓
Answer
False.Solution:
We have,
$(a+b)^2=a^2+b^2+ 2ab$
We have,
$(a+b)^2=a^2+b^2+ 2ab$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$329.25=3 \times 10^2+2 \times 10^1+9 \times 10^0+2 \times 10^{-1}+5 \times 10^{-2}$
→Simplify
$(t+s^{2})(t^{2}-s)$
→$(t+s^{2})(t^{2}-s)$
Use the properties of exponents to verify that each statement is true. $4^{\text{n}-1}=\frac{1}{4}(4)^{\text{n}}$
→Which of the following statements are true for a rectangle? Its diagonals are equal and perpendicular, and bisect each other.
What will be the units digit of the squares of the following numbers?
4583
4583
Using square root table, find the square root,
$\frac{57}{169}$
→$\frac{57}{169}$
Classify the following curve as open or closed:
Classify the following curve as open or closed:
Write the additive inverse of the following rational number: $\frac{-17}{5}$
→Classify the following polynomials as monomials, binomials, trinomials. Which polynomials do not fit in any category$?$
$x + y$
→$x + y$