A bag containe 5 black, 4white balls and 3 red balls. if a ball is selected randomwise, the probability that it is black or red ball is,
A$\frac{1}{3}$
B$\frac{1}{4}$
C$\frac{5}{12}$
D$\frac{2}{3}$
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C$\frac{5}{12}$
We know that the bag contains 5B (black), 4W(white) and 3R(red) balls.
Now,
$\text{P(B)}=\frac{5}{12}$
$\text{P(R)}=\frac{3}{12}$
$\text{P}(\text{B or R})=\text{P(B)}+\text{P(R)}$
$=\frac{5}{12}+\frac{3}{12}$
$=\frac{8}{12}=\frac{2}{3}$
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