Question
A ball falling in a lake of depth $200\, m$ shows $0.1\%$ decrease in its volume at the bottom. What is the bulk modulus of the material of the ball
✓
Answer
(a) $B = \frac{{\Delta p}}{{\Delta V/V}} = \frac{{h\rho g}}{{0.1/100}} = \frac{{200 \times {{10}^3} \times 9.8}}{{1/1000}}$
$ = 19.6 \times {10^8}N/{m^2}$
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