MCQ
A ball is dropped from a height $h$ above ground. Neglect the air resistance, its velocity $(v)$ varies with its height above the ground as
- ✓$\sqrt{2 g(h-y)}$
- B$\sqrt{2 g h}$
- C$\sqrt{2 g y}$
- D$\sqrt{2 g(h+y)}$
✓
Answer
Correct option: A.
$\sqrt{2 g(h-y)}$
a
(a)
(a)
$v=\sqrt{2 g(h-y)}$
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