A ball is projected at an angle 45^o with horizontal. It passes t… - Vidyadip

MCQ

A ball is projected at an angle $45^o$ with horizontal. It passes through a wall of height $h$ at horizontal distance $d_1$ from the point of projection and strikes the ground at a horizontal distance $(d_1 + d_2)$ from the point of projection, then $h$ is

A
$h = \frac{{2{d_1}{d_2}}}{{{d_1} + {d_2}}}$
✓
$h = \frac{{{d_1}{d_2}}}{{{d_1} + {d_2}}}$
C
$h = \frac{{\sqrt 2 {d_1}{d_2}}}{{{d_1} + {d_2}}}$
D
$h = \frac{{{d_1}{d_2}}}{{2\left( {{d_1} + {d_2}} \right)}}$

✓

Answer

Correct option: B.

$h = \frac{{{d_1}{d_2}}}{{{d_1} + {d_2}}}$

b
$y=x \tan \theta\left(1-\frac{x}{R}\right)$

$\mathrm{h}=\mathrm{d}_{1} \tan 45^{\circ}\left(1-\frac{\mathrm{d}_{1}}{\mathrm{d}_{1}+\mathrm{d}_{2}}\right)$

$\mathrm{h}=\mathrm{d}_{1} \frac{\mathrm{d}_{2}}{\mathrm{d}_{1}+\mathrm{d}_{2}}$

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