MCQ
A ball is projected from ground at an angle $45^{\circ}$ with horizontal from distance $d_1$ from the foot of a pole and just after touching the top of pole it the falls on ground at distance $d_2$ from pole on other side, the height of pole is ...........
  • A
    $2 \sqrt{d_1 d_2}$
  • B
    $\frac{d_1+d_2}{4}$
  • C
    $\frac{2 d_1 d_2}{d_1+d_2}$
  • $\frac{d_1 d_2}{d_1+d_2}$

Answer

Correct option: D.
$\frac{d_1 d_2}{d_1+d_2}$
d
(d)

Repeated.

$\tan \alpha+\tan \beta=\tan \theta$

$\frac{y}{d_1}+\frac{y}{d_2}=\tan 45^{\circ}$

$y=\left(\frac{d_1 d_2}{d_1+d_2}\right)$

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