$\int \limits_{10}^{m} d \omega=2 t^{5}-t^{2}$
$\omega=10+2 t^{5}-t^{2}$
$\frac{d \theta}{d t}=10+2 t^{5}-t^{2}$
$\int \limits_{4}^{\theta} d \theta=10+2 t^{3}-t^{2}$
$\int \limits_{4}^{\theta} d \theta=10 t+\frac{t^{4}}{2}-\frac{t^{3}}{3}$
$\theta=4+10 t+\frac{t^{4}}{2}-\frac{t^{5}}{3}$
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$(i)$ The potential difference
$(ii)$ The capacitance
$(iii)$ The charge on the plates
(Take : $g =10 \,ms ^{-2},$ the radius of earth, $R =6400 \times 10^{3}\, m ,$ Take $\left.\pi=3.14\right)$
Charge $- q $ is distributed on the surfaces as
