A ball of mass $1\, g$ and charge ${10^{ - 8}}\,C$ moves from a point $A$. where potential is $600\, volt$ to the point $B$ where potential is zero. Velocity of the ball at the point $B$ is $20\, cm/s$. The velocity of the ball at the point $A$ will be
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(a) By using $\frac{1}{2}m(v_1^2 - v_2^2) = QV$
$==>$ $\frac{1}{2} \times {10^{ - 3}}\{ v_1^2 - {(0.2)^2}\} = {10^{ - 8}}(600 - 0)$
$==>$ ${v_1} = 22.8\,cm/s$
$==>$ $\frac{1}{2} \times {10^{ - 3}}\{ v_1^2 - {(0.2)^2}\} = {10^{ - 8}}(600 - 0)$
$==>$ ${v_1} = 22.8\,cm/s$
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