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A parallel plate capacitor is charged and then disconnected from the source steady $E.M.F.$ The plates are then drawn apart farther. Again it is connected to the same source. Then :
Four point charges $-Q, -q, 2q$ and $2Q$ are placed, one at each comer of the square. The relation between $Q$ and $q$ for which the potential at the centre of the square is zero is
The two metallic plates of radius $r$ are placed at a distance $d$ apart and its capacity is $C$. If a plate of radius $r/2$ and thickness $d$ of dielectric constant $6$ is placed between the plates of the condenser, then its capacity will be
The charges on two plates of a $10\,\mu f$ capacitor are $5\,\mu C$ and $15\,\mu C$ then the potential difference across the capacitor plates is........$V$
Two point charges $-q$ and $+q$ are located at points $(0, 0, -a)$ and $(0, 0, a),$ respectively. The potential at a point $(0, 0, z)$ where $z > a$ is