A ball rises to surface at a constant velocity in a liquid whose density is $4$ times greater than that of the material of the ball. The ratio of the force of friction acting on the rising ball and its weight is
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$\mathrm{F}_{\mathrm{B}}=\mathrm{F}_{\mathrm{v}}+\mathrm{F}_{\mathrm{G}}$
$\mathrm{F}_{\mathrm{v}}=3 \rho \mathrm{vg}$
$\frac{\mathrm{F}_{\mathrm{v}}}{\mathrm{F}_{\mathrm{G}}}=\frac{3 \mathrm{pvg}}{\rho \mathrm{vg}}$
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